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Title:Novejše posplošitve Fermatove točke
Authors:ID Urlep, Tadeja (Author)
ID Hvala, Bojan (Mentor) More about this mentor... New window
Files:.pdf UN_Urlep_Tadeja_2016.pdf (2,57 MB)
MD5: DB9BE034FD2F3858D2444E92D5617A96
 
Language:Slovenian
Work type:Undergraduate thesis
Typology:2.11 - Undergraduate Thesis
Organization:FNM - Faculty of Natural Sciences and Mathematics
Abstract:Če nad stranicami trikotnika z zunanje strani narišemo enakostranične trikotnike APB, BQC in CRA, se daljice AQ, BR in CP sekajo v Fermatovi točki Fe trikotnika ABC. Diplomsko delo prinaša nekatere posplošitve tega rezultata. Pri eni nad stranicami narišemo podobne enakostranične trikotnike. Pri drugi nad stranicami na primeren način narišemo podobne (ne nujno enakokrake) trikotnike. Obe omenjeni situaciji sta posebna primera splošnejše situacije, kjer pri vsakem oglišču od obeh stranic, ki se stikata v tem oglišču, navzven odmerimo enake kote. V naslednji posplošitvi iz trikotnika na primeren način ustvarimo šestkotnik in nad stranicami tega narišemo enakostranične trikotnike. Tudi tokrat smo priča dejstvu, da se tri daljice sekajo v skupni točki. Isto se zgodi, če enakostranične trikotnike namesto navznoter narišemo navzven.
Keywords:Fermatova točka, Napoleonov izrek, posplošitve Fermatove točke, konkurentne daljice, Cevov izrek, kompleksna števila v geometriji.
Place of publishing:Maribor
Publisher:[T. Urlep]
Year of publishing:2016
PID:20.500.12556/DKUM-61481 New window
UDC:514.112.3(043.2)
COBISS.SI-ID:22594056 New window
NUK URN:URN:SI:UM:DK:I1SMXNBJ
Publication date in DKUM:29.09.2016
Views:1491
Downloads:81
Metadata:XML DC-XML DC-RDF
Categories:FNM
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Secondary language

Language:English
Title:Recent generalizations of fermat point
Abstract:If we draw equilateral triangles APB, BQC in CRA on the outside of the given triangle ABC, the three segments AQ, BR and CP intersect in the Fermat point Fe of a triangle ABC. In the diploma thesis we present some generalizations of this result. Instead of equilateral triangles we draw similar isosceles triangles. Next we draw (in an appropriate manner) similar scalene triangles. Both mentioned situations are special cases of a more general situation, where at every vertex of a triangle we draw two rays, forming the same angle with the sides of a triangle that meet in that specific vertex. Repeating this in all three vertices with possibly different angles at different vertices, we end up with three triangles APB, BQC in CRA and concurrent lines AQ, BR and CP. Finally we start with a triangle and form a certain hexagon out of it. On the sides of this hexagon we again erect equilateral triangles and end up again with three concurrent lines. The same is true if the equilateral triangles are erected on the inside.
Keywords:Fermat point, Napoleon's theorem, generalizations of Fermat point, concurrent lines, Ceva's theorem, complex numbers and geometry


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